50+x^2=200+5x

Solution for 50+x^2=200+5x equation:

50+x^2=200+5x

We move all terms to the left:

50+x^2-(200+5x)=0

We add all the numbers together, and all the variables

x^2-(5x+200)+50=0

We get rid of parentheses

x^2-5x-200+50=0

We add all the numbers together, and all the variables

x^2-5x-150=0

a = 1; b = -5; c = -150;
Δ = b2-4ac
Δ = -52-4·1·(-150)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*1}=\frac{30}{2}
=15
$